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Quadratic Equations

ax² + bx + c = 0 ? :confused:

D = b² - 4ac

x1/2 = [ -b +/- sqrt(D) ] / 2a

If D = 0 you'll have one "real" solution with multiplicity = 2 [form: (x-a)²=0]
D > 0 you'll have two "real" solutions
D < 0 you'll have two "imaginary" solutions
 
The easiest method is to factor (if you can). The next best thing is to use the quadratic formula:

Code:
      -b (+/-) sqrt(b^2 - 4ac)
x = -----------------------------
                   2a

Easy to remember, easy to use. :D
 
Or use a TI-83+ :p
Then again, I'm in calculus, so a lot of stuff like this is done by calculator to save time.
 
Originally posted by The Red Guy
Solve simulatneously, which means like equate first equation to 2nd:

1 = 2

Or draw a curve. :)
Try not to use this unless you cannot solve using a criss cross method. :)
 
Well...for calculus we aren't allowed our Ti-83's. It becomes difficult factoring when you get a value other than 1 for a (okay, 2 is easy...but I don't want to waste time guessing and checking on anything 4 and above...). So, doing the quadratic formula manually is much easier...
 
Similar situation to me.

the banishment of all calculators was a major blow. I had to learn how to factor again.

and then calculus came and I wished i was in elementary school again. what I would give to have a map to colour, or maybe a story to read, instead of all this differentiation BS.
 
Originally posted by Mahoro
Or use a TI-83+ :p
Then again, I'm in calculus, so a lot of stuff like this is done by calculator to save time.

I get to use TI's Derive software... it makes it even easier again, once you know what you're doing. :)
 
Originally posted by conkermaniac
The easiest method is to factor (if you can). The next best thing is to use the quadratic formula:

Code:
      -b (+/-) sqrt(b^2 - 4ac)
x = -----------------------------
                   2a

Easy to remember, easy to use. :D

USE NEWTONS METHOD!! :)
 
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